Integrand size = 30, antiderivative size = 179 \[ \int (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)} \, dx=\frac {12 i a (e \cos (c+d x))^{7/2} \sec ^2(c+d x)}{35 d \sqrt {a+i a \tan (c+d x)}}+\frac {32 i a (e \cos (c+d x))^{7/2} \sec ^4(c+d x)}{35 d \sqrt {a+i a \tan (c+d x)}}-\frac {2 i (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)}}{7 d}-\frac {16 i (e \cos (c+d x))^{7/2} \sec ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d} \]
[Out]
Time = 0.64 (sec) , antiderivative size = 179, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {3596, 3578, 3583, 3569} \[ \int (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)} \, dx=-\frac {2 i \sqrt {a+i a \tan (c+d x)} (e \cos (c+d x))^{7/2}}{7 d}+\frac {32 i a \sec ^4(c+d x) (e \cos (c+d x))^{7/2}}{35 d \sqrt {a+i a \tan (c+d x)}}-\frac {16 i \sec ^2(c+d x) \sqrt {a+i a \tan (c+d x)} (e \cos (c+d x))^{7/2}}{35 d}+\frac {12 i a \sec ^2(c+d x) (e \cos (c+d x))^{7/2}}{35 d \sqrt {a+i a \tan (c+d x)}} \]
[In]
[Out]
Rule 3569
Rule 3578
Rule 3583
Rule 3596
Rubi steps \begin{align*} \text {integral}& = \left ((e \cos (c+d x))^{7/2} (e \sec (c+d x))^{7/2}\right ) \int \frac {\sqrt {a+i a \tan (c+d x)}}{(e \sec (c+d x))^{7/2}} \, dx \\ & = -\frac {2 i (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)}}{7 d}+\frac {\left (6 a (e \cos (c+d x))^{7/2} (e \sec (c+d x))^{7/2}\right ) \int \frac {1}{(e \sec (c+d x))^{3/2} \sqrt {a+i a \tan (c+d x)}} \, dx}{7 e^2} \\ & = \frac {12 i a (e \cos (c+d x))^{7/2} \sec ^2(c+d x)}{35 d \sqrt {a+i a \tan (c+d x)}}-\frac {2 i (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)}}{7 d}+\frac {\left (24 (e \cos (c+d x))^{7/2} (e \sec (c+d x))^{7/2}\right ) \int \frac {\sqrt {a+i a \tan (c+d x)}}{(e \sec (c+d x))^{3/2}} \, dx}{35 e^2} \\ & = \frac {12 i a (e \cos (c+d x))^{7/2} \sec ^2(c+d x)}{35 d \sqrt {a+i a \tan (c+d x)}}-\frac {2 i (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)}}{7 d}-\frac {16 i (e \cos (c+d x))^{7/2} \sec ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d}+\frac {\left (16 a (e \cos (c+d x))^{7/2} (e \sec (c+d x))^{7/2}\right ) \int \frac {\sqrt {e \sec (c+d x)}}{\sqrt {a+i a \tan (c+d x)}} \, dx}{35 e^4} \\ & = \frac {12 i a (e \cos (c+d x))^{7/2} \sec ^2(c+d x)}{35 d \sqrt {a+i a \tan (c+d x)}}+\frac {32 i a (e \cos (c+d x))^{7/2} \sec ^4(c+d x)}{35 d \sqrt {a+i a \tan (c+d x)}}-\frac {2 i (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)}}{7 d}-\frac {16 i (e \cos (c+d x))^{7/2} \sec ^2(c+d x) \sqrt {a+i a \tan (c+d x)}}{35 d} \\ \end{align*}
Time = 2.09 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.45 \[ \int (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)} \, dx=\frac {e^3 \sqrt {e \cos (c+d x)} (35 i \cos (c+d x)+i \cos (3 (c+d x))+70 \sin (c+d x)+6 \sin (3 (c+d x))) \sqrt {a+i a \tan (c+d x)}}{70 d} \]
[In]
[Out]
Time = 8.88 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.44
method | result | size |
default | \(\frac {2 i \sqrt {e \cos \left (d x +c \right )}\, \sqrt {a \left (1+i \tan \left (d x +c \right )\right )}\, e^{3} \left (-6 i \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )+\cos ^{3}\left (d x +c \right )-16 i \sin \left (d x +c \right )+8 \cos \left (d x +c \right )\right )}{35 d}\) | \(78\) |
[In]
[Out]
none
Time = 0.25 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.56 \[ \int (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)} \, dx=\frac {\sqrt {2} \sqrt {\frac {1}{2}} {\left (-5 i \, e^{3} e^{\left (6 i \, d x + 6 i \, c\right )} - 35 i \, e^{3} e^{\left (4 i \, d x + 4 i \, c\right )} + 105 i \, e^{3} e^{\left (2 i \, d x + 2 i \, c\right )} + 7 i \, e^{3}\right )} \sqrt {e e^{\left (2 i \, d x + 2 i \, c\right )} + e} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} e^{\left (-\frac {5}{2} i \, d x - \frac {5}{2} i \, c\right )}}{140 \, d} \]
[In]
[Out]
Timed out. \[ \int (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)} \, dx=\text {Timed out} \]
[In]
[Out]
none
Time = 0.43 (sec) , antiderivative size = 202, normalized size of antiderivative = 1.13 \[ \int (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)} \, dx=\frac {{\left (7 i \, e^{3} \cos \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) - 5 i \, e^{3} \cos \left (\frac {7}{5} \, \arctan \left (\sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ), \cos \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right )\right )\right ) - 35 i \, e^{3} \cos \left (\frac {3}{5} \, \arctan \left (\sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ), \cos \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right )\right )\right ) + 105 i \, e^{3} \cos \left (\frac {1}{5} \, \arctan \left (\sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ), \cos \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right )\right )\right ) + 7 \, e^{3} \sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ) + 5 \, e^{3} \sin \left (\frac {7}{5} \, \arctan \left (\sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ), \cos \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right )\right )\right ) + 35 \, e^{3} \sin \left (\frac {3}{5} \, \arctan \left (\sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ), \cos \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right )\right )\right ) + 105 \, e^{3} \sin \left (\frac {1}{5} \, \arctan \left (\sin \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right ), \cos \left (\frac {5}{2} \, d x + \frac {5}{2} \, c\right )\right )\right )\right )} \sqrt {a} \sqrt {e}}{140 \, d} \]
[In]
[Out]
\[ \int (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)} \, dx=\int { \left (e \cos \left (d x + c\right )\right )^{\frac {7}{2}} \sqrt {i \, a \tan \left (d x + c\right ) + a} \,d x } \]
[In]
[Out]
Time = 6.15 (sec) , antiderivative size = 96, normalized size of antiderivative = 0.54 \[ \int (e \cos (c+d x))^{7/2} \sqrt {a+i a \tan (c+d x)} \, dx=\frac {e^3\,\sqrt {e\,\cos \left (c+d\,x\right )}\,\sqrt {\frac {a\,\left (\cos \left (2\,c+2\,d\,x\right )+1+\sin \left (2\,c+2\,d\,x\right )\,1{}\mathrm {i}\right )}{\cos \left (2\,c+2\,d\,x\right )+1}}\,\left (\sin \left (c+d\,x\right )+\frac {3\,\sin \left (3\,c+3\,d\,x\right )}{35}+\frac {\cos \left (c+d\,x\right )\,1{}\mathrm {i}}{2}+\frac {\cos \left (3\,c+3\,d\,x\right )\,1{}\mathrm {i}}{70}\right )}{d} \]
[In]
[Out]